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If the work function of a metal is 6.63

Web13. The threshold wavelength for emission from a metallic surface is 500 nm. What is the work function for that particular metal? Threshold frequency = c/λ Threshold frequency … Web28 feb. 2024 · Explanation: Einstein's photoelectric equation is: hf = Φ+ 1 2mv2 max, where: h = Planck's constant ( 6.63 ⋅ 10−34J s) f = frequency ( m) Φ = work function ( J) m = mass of the charge-carrier ( kg) vmax = maximum velocity ( ms−1) However, f = c λ, where: c = speed of light ( ~3.00⋅ 108ms−1) λ = wavelength ( m) hc λ = Φ + 1 2 mv2 max

Table 30.5 shows the work functions of several different metals. a ...

Web8 sep. 2024 · The work function of metal is 6 eV. If light of frequency 1 x 10¹⁵ Hz is incident on the metal, intensity of light is increased 4 times, then 1) No photoelectron will … WebIf the work function of a metal is 6.63 × 10-19 J, the maximum wavelength of the photon required to remove a photoelectron from the metal is nm. (Nearest integer) [Given: h=6.63 × 10-34 J s, and c =3 × 108 m s -1 ] Q. link ctr https://christinejordan.net

Table 30.5 shows the work functions of several different metals. a ...

WebWhat is its de Broglie wavelength? (h = 6.63 ´ 10-34 J×s, me = 9.11 ´ 10-31 kg, and 1 eV = 1.60 ´ 10-19 J) A. 1.1*10^-10 m B. 1.5*10^-10 m C. 1.9*10^-10 m D. 2.3*10^-10 m E. … WebThe work function of sodium metal is 4.41 $$ \times $$ 10–19 J. If photons of wavelength 300 nm are incident on the metal, the kinetic energy of the e... View Question EXAM … WebIf the work function for a certain metal is 3.2 × 1 0 − 19 joule and it is illuminated with light of frequency 6 × 1 0 14 Hz. The maximum kinetic energy of the photo-electrons would be … link css to html tag

Threshold frequency and threshold wavelength of metal - The Fact …

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If the work function of a metal is 6.63

Physics Chapter 30 Flashcards Quizlet

Web(a) If the work function for a certain metal is 1.5eV,what is the stopping potential for electrons ejected from the metal when the light of wavelength 500nM shines on the metal? (b) What is the maximum speed of the ejected electrons from … WebHow do you find the work function of a material? The photoelectric equation involves; h = the Plank constant 6.63 x 10 – 34 J s. f = the frequency of the incident light in hertz (Hz) &phi = the work function in joules (J) E k = the maximum kinetic energy of the emitted electrons in joules (J) Does work function depend on metal?

If the work function of a metal is 6.63

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WebThe work function of a certain metal is 3.31 × 10^-19 J. Then, the maximum kinetic energy of photoelectrons emitted by incident radiation of wavelength 5000 A is (Given h = 6.62 × …

Web31 aug. 2024 · The work function can be written as the following formula: Φ = − eφ − E F where e is the charge of an electron, φ is the electrostatic potential in the vacuum nearby … Web29 mrt. 2024 · Question 9 Light of wavelength 2000 Å falls on a metal surface of work function 4.2 eV. (a) What is the kinetic energy (in eV) of the fastest electrons emitted …

WebTable 30.5 shows the work functions of several different metals. a Which metal requires the highest frequency of electromagnetic waves to release electrons?. b Which metal will … Web20 apr. 2006 · (a) If the work function for a certain metal is 1.5 eV, what is its stopping potential for electrons ejected from the metal when light of wavelength 337 nm shines on …

WebThe equation for work function is: W = hf So, this is rearranged to: f = W/h where h is planck's constant. Therefore, if we know the work function then we can work out the threshold frequency. Don't forget to convert 3eV into J. 1eV = 1.6 x 10^ {-19} J. f = (3 x 1.6 x 10^ {-19})/ (6.63 x 10^ {-34}) f = 7.24 x 10^ {14} Hz

WebWork function of a metal is 6.63×10^-19 find the threshold frequency of it Let's Ask & Get Answers LOG IN SIGN UP hot wheels unleashed battle passWebSum If the work function of a metal is 3 eV, calculate the threshold wavelength of that metal. (Velocity of light = 3 x 10 8 m/s, Planck’s constant = 6.63 x 10 –34 J.s.; 1 eV = 1.6 … link ctsWebStudy with Quizlet and memorize flashcards containing terms like 1) An ideal blackbody absorbs all of the light that is incident on it., 2) The distribution of energy in the … link css style sheetWebNote that 6.63 eV = 1.602 * 10^-19 joules, this is E. Therefore: f = E/h f = (1.602 * 10^-19)/ (6.63 * 10^-34) f = 2.416 * 10^14 Hz ( 241.6THz) 3 1 More answers below Faraz Raza 4 y W/h= Threshold energy 6.63e-19/6.34e-34 , will give the frequency of the metal.. Ans= 1.0457413e+15 Jess H. Brewer Physics professor since 1977. Upvoted by Steven Merz linkcure therapeuticsWeb26 dec. 2024 · If the work function of the metal is 2.46 eV, what is the maximum kinetic energy of emitted photoelectrons? (For convenience, note that a photon of wavelength … hot wheels unleashed big wWeb20 jul. 2011 · The point of calculating Planck's constant would be to assess the accuracy of your experiment. You can tell from the equation of the photoelectric effect that Planck's … link curationWeb28 jan. 2024 · Two radiations with photon energies 0.9 eV and 3.3 eV respectively are falling on a metallic surface successively. If the work function of the metal is 0.6 eV, then the ratio of maximum speeds of emitted electrons will be a) 1 : 4 b) 1 : 3 c) 1 : 1 d) 1 : 9 Answer: b) 1 : 3 Solution: mv 2 = mv 12 = 0.9 – 0.6 = 0.3 ………………. (1) link cubes online